Quantities of Motion

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When describing a particle's motion, it is helpful to note that motion is just the change in a particle's position over a certain time. With this, we note the first quantity of use which is

Position (r) – the place wherein a particle is in space

The symbol for position may vary based on the problem. Since there is a change in the particle’s position, it is helpful to quantify this as well. There are two ways to quantify this change.

Displacement (Δr) – the change in position of a particle in its motion
Distance (s) – the length of the path of a particle in its motion

The SI unit for both distance and displacement is the meter. Distance and displacement have similar definitions yet differ immensely.
Distance measures the path taken by the particle, which means it goes through the entire path, while displacement measures the shortest distance between the starting and ending position, which is a straight line.

The displacement between the two points is much smaller than the distance travelled.

One property is that distance will always be greater than or equal to the displacement.

Question 1

(LSM CQ3.5) Does a car’s odometer measure distance traveled or displacement?

Answer

A car's odometer measures distance travelled. If it measured displacement, it would be zero if you parked your car at the garage!

Exercise 1

(HRK E2.11) A woman walks 250 m in the direction 35° east of north, then 170 m directly east. Compare the magnitude of her displacement with the distance she walked.

Solution

The diagram can be drawn as below, with the original position at the origin.
The movement of the woman.

It can be seen that the displacement is less than the distance. The distance is simply the sum of the lengths the woman walked, which is 250m + 170m = 420m.

The displacement on the other hand can be calculated via the pythagorean theorem. To get the horizontal and vertical components of the 35° walk, we use trigonometry.

Δr=[250cos(35°)]²+[250sin(35°)+170]²
Δr370m
Recall that displacement may be less than the distance; this shows this fact.

Recall that we noted that motion is the change of position over a certain time. With this, it is a necessity that we introduce time to quantify how slow or fast an object is moving.

Time (t) – the time elapsed

Now that we have added time, we can now analyze how fast or slow a certain motion occurs, which gives us two new quantities.

Velocity (v) – the rate of change of position over time
Speed (v) – the amount of distance travelled over time

Since they are how fast we can travel a certain amount in a certain time, the SI unit for both speed and velocity is meters per second. To calculate the average velocity of a particle, just take the displacement and divide it by the time it took to travel that displacement.

v̅=ΔxΔt

Here, Δx (read as "delta x") means the change in the value x, or position. It can be calculated below, which is the final position minus the initial position.

Δx=(xfx0)

As with displacement and distance, velocity and speed are different as well. Velocity measures the displacement done over a length of time, while speed measures the distance travelled.

Running around a track means you have no velocity, but you do have speed.

Just like distance may not equal displacement, velocity may not equal speed. If one goes around a circular track and ends up back where they started, their distance will be the circumference of the track, but their displacement will be zero.

Question 2

(LSM CQ3.8) Does the speedometer of a car measure speed or velocity?

Answer

A car's speedometer measures the speed of travel. If it measured velocity, it would read negative when you start to turn around!

Exercise 2

(LSM P3.30) A woodchuck runs 20 m to the right in 5 s, then turns and runs 10 m to the left in 3 s.
(a) What is the average velocity of the woodchuck?
(b) What is its average speed?

Solution

The displacement of the woodchuck is 20m+(−10m)=10m. The total time elapsed is then 8s. With this, we can calculate the velocity: 10m8s=1.25m/s For the speed, we add the two lengths together (since we need the distance), so we have 20m+10m=30m. We can then calculate speed: 30m8s=3.75m/s

While it is useful to have the average velocity, we sometimes need the instantaneous velocity of a particle; in other words, the velocity of a particle at a given instance of time.

To help find this, let's say we can get the position of a particle at any given time. For example, let's say the object is moving at a constant velocity, so at 1s it is at 1m, while at 2s it is at 2m. In other words, we can plug in time, and get a position value out.

Position as a function of time.

We can write this as a function, or x(t). Now, let's imagine having a certain time t and adding a little more to it, let's call Δt.

Position at time t and t+Δt.

If we want the average velocity between these two values, we use our formula.

v=ΔxΔt=(xfx0)(tft0)

Now, let's subtitute in our two values.

v=x(t+Δt)x(t)t+Δtt=x(t+Δt)x(t)Δt

Does this look familiar? This looks like the equation for the limit-definition of a derivative. Letting Δt approach zero, we get that the derivative of position is velocity.

dxdt=v

How is this useful? We can now get the velocity of an object at any given time if we please. We examine this in more detail in our study of motion graphs.

Question 3

(HRK Q2.12) When the velocity is constant, can the average velocity over any time interval differ from the instantaneous velocity at any instant? If so, give an example; if not, explain why.

Solution

No. The instantaneous velocity must be the same for every single given time, and the average of a constant value is just the constant itself.

Most particles don't have a constant velocity or speed. For example, gravity pulls us all down at a constant rate. This rate of change is helpful, so we should give a quantity to it.

Acceleration (a) – the rate of change of velocity over time

Note that unlike what you may think, acceleration can be negative, as it is a vector. Negative acceleration is also called deceleration. If acceleration is zero, it means that the velocity is constant. In other words, the change of velocity over time is zero.

Acceleration can be negative, called deceleration.

The SI unit for acceleration is meters per second squared, or it can be written as (m/s)/s. In the figure above, it highlights how acceleration is how fast the velocity is changing per second; how many "m/s" it changes per "s".

As can be seen, deceleration occurs when the velocity and acceleration don't share the same sign; here, positive means "going down", while negative means "going up".

Calculating the average acceleration is similar to calculating the average velocity. It is the change in velocity over the time elapsed to change that velocity.

a̅=ΔvΔt

Question 4

(HRK Q2.15) Can the velocity of an object reverse direction when its acceleration is constant? If so, give an example; if not, explain why.

Answer

Yes.
This is possible if the direction of acceleration is the opposite direction of the velocity. The particle slows down, then goes the other way, as the velocity is slowly going the other way.

Exercise 3

(LSM P3.37) A cheetah can accelerate from rest to a speed of 30.0 m/s in 7.00 s. What is its acceleration?

Solution

While not stated, we can infer the initial velocity is 0m/s, as it was at rest. Then, it accelerated to 30m/s. The total time elapsed is then 7s. With this, we can calculate the acceleration: (30.0m/s − 0m/s)7.00s=4.29m/s²

Recall what we did to get the instantaneous velocity; we can do the same argument to get the instantaneous acceleration. We will analyze this later.

dvdt=a

One thing to note is that some of these quantities require a direction; for example, velocity doesn't make sense unless you tell which way you are going, and acceleration requires a direction to tell if it is decelerating or accelerating. Later, we will find out that these things which need direction are called vectors.